## Chemistry (4th Edition)

(a) $$[B] = 6.00$$ (b) $$[B]= 6.00$$ (c) $$[B] = 9.00$$
1. Calculate the Kc using the first diagram: (a) $$K_c = \frac{(4)^2}{(6)^2} = 0.444$$ (b) $$K_c = \frac{4}{6} = 0.667$$ (c) $$K_c = \frac{4}{6^2} = 0.111$$ 2. Find "b" for equilibrium: (a) $$[B] = \sqrt{(0.444)(9)^2)} = 6.00$$ (b) $$[B] = (0.667)(9) = 6.00$$ (c) $$[B] = (0.111)(9)^2 = 9.00$$