Answer
$\therefore$ $P_{O_2}$=1.601 atm
Work Step by Step
$χ_{O_2}=(n_{O_2})/(n_{Total})$
$n_{Total}=4.10 + 2.38 + 0.917 =7.397mol$
$n_{O_2}=4.10mol$
$χ_{O_2}=\frac{4.10}{7.397}$
$χ_{O_2}= 0.5542 $
Now
$P_{O_2} = χ_{O_2} \times P_{total}$
= $0.5542\times 2.89 $
$P_{O_2}$=1.601 atm
