Answer
$χ_{CO_2} = 0.0138$
Work Step by Step
$$χ_{CO_2} = \frac{n_{CO_2}}{n_{Total}}$$
$n_{Total} = 0.756 + 0.189 + 0.0132 = 0.9582 mol$
$n_{CO_2} = 0.0132mol $
$χ_{CO_2} = \frac{0.0132}{0.9582}$
$χ_{CO_2} = 0.0138$
Chemistry (4th Edition)
by Burdge, Julia
Published by
McGraw-Hill Publishing Company
ISBN 10:
0078021529
ISBN 13:
978-0-07802-152-7
Chapter 10 - Section 10.5 - Gas Mixtures - Checkpoint - Page 451: 10.5.2
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