Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 10 - Questions and Problems - Page 470: 10.14

Answer

$0.764atm$, $77.5KPa$

Work Step by Step

First, we find the atmospheric pressure in $atm$ As $760mm\space Hg=1atm$ $\implies 1mm\space Hg=\frac{1}{760}atm$ $\implies 581mm\space Hg=581\times \frac{1}{760}=0.764atm$ Now, we find atmospheric pressure in $KPa$ As As $760mm\space Hg=101.325KPa$ $\implies 1mm\space Hg=\frac{101.325}{760}KPa$ $\implies 581mm\space Hg=581\times \frac{101.325}{760}=77.5KPa$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.