Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 10 - Questions and Problems - Page 470: 10.13

Answer

$0.493atm$, $0.500 bar$, $375 torr$, $5.00\times 10^4 Pa$

Work Step by Step

We can convert $375\space mm\space Hg$ in to the given units as follows: As $760mm\space Hg=1atm$ $\implies 1mm\space Hg=\frac{1atm}{760}$ $\implies 375mm\space Hg=\frac{375}{760}atm=0.493atm$ Now, we convert it into bar As $760mm\space Hg=1.01325bar$ $\implies 1mm\space Hg=\frac{1.01325bar}{760}$ $\implies 375mm\space Hg=\frac{375\times 1.01325}{760}bar=0.500 bar$ We convert it into torr As $760mm\space Hg=760torr$ $\implies 1mm\space Hg=\frac{760torr}{760}$ $\implies 375mm\space Hg=\frac{375\times 760}{760}torr=375torr$ We convert it into Pascals As $760mm\space Hg=101.325KPa$ $\implies 1mm\space Hg=\frac{101.325KPa}{760}$ $\implies 375mm\space Hg=\frac{375\times 101.325KPa}{760}\times\frac{1000Pa}{1KPa}=5.00\times 10^4Pa$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.