Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 1 - Section 1.6 - Using Units and Solving Problems - Checkpoint - Page 25: 1.6.1


b) 0.535 g/$cm^{3}$

Work Step by Step

535 kg/$m^{3}$ = 535$\frac{kg}{m^{3}} \times \frac{1000g}{1kg} \times\frac{1m^{3}}{10^{6}cm^{3}}$ = 0.535 $g/cm^{3}$
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