Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 1 - Section 1.5 - Uncertainty in Measurement - Checkpoint - Page 22: 1.5.4


e) $1\times10^{-5}$

Work Step by Step

$(6.266-6.261)\div522.0 = 0.005\div522.0$ Here, 0.005 is the operand with the least significant figures. Number of significant figures in 0.005 = 1. The final answer should be rounded to one significant figure. Hence, $0.005\div522.0$ = $1\times10^{-5}$
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