Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 9 - Chemical Bonding I - Questions & Problems: 9.88

Answer

Please see the work below.

Work Step by Step

We know that $\Delta H^{\circ}_f=872.8\frac{KJ}{mol}+716\frac{KJ}{mol}-4\times 414\frac{KJ}{mol}=-67\frac{KJ}{mol}$
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