Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 9 - Chemical Bonding I - Questions & Problems - Page 407: 9.77


Please see the work below.

Work Step by Step

We know that a. $520-295=225\frac{KJ}{mol}$ b. $495.9-328=167.9\frac{KJ}{mol}$ c. $418.7-349=69.7\frac{KJ}{mol}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.