Answer
Please see the work below.
Work Step by Step
We know that the given required reaction is given as
$F_2(g)\rightarrow F_(g)+F_(g)$
now $\Delta H^{\circ}=\frac{156.9}{2}=78.45\frac{kJ}{mol}$
Chemistry 12th Edition
by Chang, Raymond; Goldsby, Kenneth
Published by
McGraw-Hill Education
ISBN 10:
0078021510
ISBN 13:
978-0-07802-151-0
Chapter 9 - Chemical Bonding I - Questions & Problems - Page 406: 9.71
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