Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 7 - Quantum Theory and the Electronic Structure of Atoms - Questions & Problems - Page 316: 7.16

Answer

(a) $4.0\times10^{2}\,nm$ (b) $5.0\times10^{-19}\,J$

Work Step by Step

(a) $c=\nu\lambda$ where $c$ is the speed of light, $\nu$ is the frequency and $\lambda$ is the wavelength. $\implies \lambda=\frac{c}{\nu}=\frac{3.00\times10^{8}\,m/s}{7.5\times10^{14}\,s^{-1}}=4.0\times10^{-7}\,m$ $=4.0\times10^{2}\times10^{-9}\,m=4.0\times10^{2}\,nm$ (b) Energy $E=h\nu=(6.626\times10^{-34}\,J\cdot s)(7.5\times10^{14}\,s^{-1})$ $=5.0\times10^{-19}\,J$
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