Answer
$3.19\times10^{-19}\,J$
Work Step by Step
$E=\frac{hc}{\lambda}=\frac{(6.626\times10^{-34}\,J\cdot s)(3.00\times10^{8}\,m/s)}{624\times10^{-9}\,m}$
$=3.19\times10^{-19}\,J$
Chemistry 12th Edition
by Chang, Raymond; Goldsby, Kenneth
Published by
McGraw-Hill Education
ISBN 10:
0078021510
ISBN 13:
978-0-07802-151-0
Chapter 7 - Quantum Theory and the Electronic Structure of Atoms - Questions & Problems - Page 316: 7.15
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