Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 6 - Thermochemistry - Questions & Problems: 6.33

Answer

Please see the work below.

Work Step by Step

We know that $q=(6.22\times 10^{3})\times (0.385)(324.3-20.5)=7.28\times 10^5J=728KJ$
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