Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 6 - Thermochemistry - Questions & Problems - Page 263: 6.26

Answer

Please see the work below.

Work Step by Step

We know that $1.26\times 10^4g\space NO_2\times \frac{1mol\space NO_2}{46.01g\space NO_2}\times \frac{114.6kJ}{2mol\space NO_2}=1.57\times 10^4kJ$
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