Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 6 - Thermochemistry - Questions & Problems - Page 262: 6.16

Answer

(a) 0 (b) -9.5 J (c) -18 J

Work Step by Step

(a) $w=-P\Delta V=-(0)\Delta V=0$ Because the external pressure is 0, $w=0$. (b) $\Delta V=89.3\,mL-26.7\,mL=62.6\,mL=0.0626\,L$ $w=-P\Delta V=-(1.5\,atm)(0.0626\,L)$ $=-0.0939\,L\cdot atm=-0.0939\,L\cdot atm\times\frac{101.3\,J}{1\,L\cdot atm}$ $=-9.5\,J$ (c) $w=-P\Delta V=-(2.8\,atm)(0.0626\,L)$ $=-0.17528\,L\cdot atm=-0.17528\,L\cdot atm\times\frac{101.3\,J}{1\,L\cdot atm}$ $=-18\,J$
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