Answer
(a) 0
(b) $-3.1\times10^{2}\,J$
(c) $-1.4\times10^{3}\,J$
Work Step by Step
(a) $w=-P\Delta V=-(0)(5.4\,L-1.6\,L)=0$
Because the external pressure is 0, $w=0$.
(b) $w=-P\Delta V=-(0.80\,atm)(5.4\,L-1.6\,L)$
$=-3.04\,L\cdot atm=-3.04\,L\cdot atm\times\frac{101.3\,J}{1\,L\cdot atm}$
$=-3.1\times10^{2}\,J$
(c) $w=-P\Delta V=-(3.7\,atm)(5.4\,L-1.6\,L)$
$=-14.06\,L\cdot atm=-14.06\,L\cdot atm\times\frac{101.3\,J}{1\,L\cdot atm}$
$=-1.4\times10^{3}\,J$
