Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 5 - Gases - Questions & Problems - Page 223: 5.143

Answer

Please see the work below.

Work Step by Step

Let us assume that each gas obey's gas law so $Partial \space pressure= Percentage \space composition \times total\space pressure$ We plug in the known values to obtain: $P_{CO_2}=0.965\times 9\times 10^6Pa=8.7\times10^6Pa=8.7MPa$ $P_{N_2}=0.035\times 9\times 10^6Pa=0.31\times 10^6Pa=310KPa$ $P_{SO_2}=0.0015\times 9\times 10^6Pa=0.0014\times10^6Pa=1.4KPa$
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