Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 5 - Gases - Questions & Problems - Page 223: 5.142


Please see the work below.

Work Step by Step

We know that $P=(\frac{6}{760})\times 101000=797.36Pa$ As $PV=nRT$ This can be rearranged as: $\frac{V}{n}=\frac{RT}{P}$ We plug in the known values to obtain: $\frac{V}{n}=\frac{8.31\times 220}{797.36}=2.293\frac{m^3}{mol}=2293\frac{L}{mol}$
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