Answer
Please see the work below.
Work Step by Step
We can find the partial pressure of $N_2$ as:
$N_2=\frac{1}{6}\times 866mmHg=144.3mmHg$
We can find the partial pressure of $H_2$ as:
$H_2=\frac{3}{6}\times 866mmHg=433mmHg$
Chemistry 12th Edition
by Chang, Raymond; Goldsby, Kenneth
Published by
McGraw-Hill Education
ISBN 10:
0078021510
ISBN 13:
978-0-07802-151-0
Chapter 5 - Gases - Questions & Problems - Page 218: 5.74
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