Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 5 - Gases - Questions & Problems - Page 218: 5.61


Please see the work below.

Work Step by Step

The reaction can be shown as: ${H_2}_{(g)}+{Cl_2}_{(g)}\rightarrow {2HCl}_{(g)}$ We know that: $PV=nRT$ We plug in the known values to obtain: $(101000)(0.0056)=n(8.31)(273)$ $n=0.249 \space moles$ As the mole ratio of $H_2:HCl=1:2$ The moles of $HCl=0.249\times 2=0.5 \space moles$ Finally, the mass of $HCl=moles \times molar mass=0.5\times 36.5=18.2g$
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