## Chemistry 12th Edition

The reaction can be shown as: ${H_2}_{(g)}+{Cl_2}_{(g)}\rightarrow {2HCl}_{(g)}$ We know that: $PV=nRT$ We plug in the known values to obtain: $(101000)(0.0056)=n(8.31)(273)$ $n=0.249 \space moles$ As the mole ratio of $H_2:HCl=1:2$ The moles of $HCl=0.249\times 2=0.5 \space moles$ Finally, the mass of $HCl=moles \times molar mass=0.5\times 36.5=18.2g$