Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 5 - Gases - Questions & Problems: 5.48

Answer

Please see the work below.

Work Step by Step

We know that: $\rho=\frac{PM}{RT}$ We plug in the known values to obtain: $\rho=\frac{0.96\times 81}{0.0821\times 319}=2.97\frac{g}{L}$
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