Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 5 - Gases - Questions & Problems - Page 217: 5.35


Please see the work below.

Work Step by Step

We know that: $\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$ This can be rearranged as: $V_2=\frac{P_1V_1T_2}{T_1P_2}$ We plug in the known values to obtain: $V_2=\frac{1.2\times 2.5\times 25}{248\times 0.003}=840L$
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