Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 5 - Gases - Questions & Problems - Page 216: 5.32

Answer

Please see the work below.

Work Step by Step

According to ideal gas equation $PV=nRT$ This can be rearranged as $P=\frac{nRT}{V}$ We plug in the known values to obtain: $P=\frac{6.9\times 0.0821\times 335}{30.4}=6.24atm$
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