## Chemistry 12th Edition

We know that: $P_fV_f=P_iV_i$ This can be rearranged as: $V_f=\frac{P_iV_i}{P_f}$ We plug in the known values to obtain: $V_f=\frac{1.2(3.8)}{6.6}=0.69L$ (b) We know that $P_f=\frac{P_iV_i}{V_f}$ We plug in the known values to obtain: $P_f=\frac{1.2(3.8)}{0.075}=60.8atm$