## Chemistry 12th Edition

We know that $molar\space mass \space of C_4H_5N_2O=4\times 12.0+5\times 1.0+2\times 14+1\times 16.0=97\frac{g}{mol}of C_4H_5N_2O$ Now, we can find the ratio as: $\frac{194.19}{97}=2$ It shows that the ratio of the empirical formula to the molecular formula is 2. Hence, we multiply the subscripts of the empirical formula by 2, and we obtain the molecular formula as: $C_8H_{10}N_4O_2.$