Answer
The electronic configurations of the following ions are:
$V^{5+} = [Ar]3d^{0}4s^{0}$
$Cr^{3+} = [Ar]3d^{2}4s^{0}$
$Mn^{2+} = [Ar]3d^{5}4s^{0}$
$Fe^{3+} = [Ar]3d^{5}4s^{0}$
$Cu^{2+} = [Ar]3d^{9}4s^{0}$
$Sc^{3+} = [Ar]3d^{0}4s^{0}$
$Ti^{4+} = [Ar]3d^{0}4s^{0}$
Work Step by Step
The electronic configurations of the following ions are:
$V^{5+} = [Ar]3d^{0}4s^{0}$
$Cr^{3+} = [Ar]3d^{2}4s^{0}$
$Mn^{2+} = [Ar]3d^{5}4s^{0}$
$Fe^{3+} = [Ar]3d^{5}4s^{0}$
$Cu^{2+} = [Ar]3d^{9}4s^{0}$
$Sc^{3+} = [Ar]3d^{0}4s^{0}$
$Ti^{4+} = [Ar]3d^{0}4s^{0}$