Chapter 2 - Atoms, Molecules, and Ions - Questions & Problems: 2.7

$1\times10^8$ helium atoms

Work Step by Step

diameter of helium atom: $1\times10^2pm$ = $1\times10^{-10}m$ distance = 1 cm = $1\times10^{-2}m$ number of helium atoms = $\frac{1\times10^{-2}}{1\times10^{-10}}$ = $1\times10^8$ helium atoms

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