Answer
$E = \frac{hc}{\lambda} = \frac{(3*10^{8}) * (6.63*10^{-34})}{2.4*10^{-13}} = 8.3*10^{-13}m = 8.3*10^{-4} nm$
This wavelength is in the X-ray region of electromagnetic spectrum
Work Step by Step
$E = \frac{hc}{\lambda} = \frac{(3*10^{8}) * (6.63*10^{-34})}{2.4*10^{-13}} = 8.3*10^{-13}m = 8.3*10^{-4} nm$
This wavelength is in the X-ray region of electromagnetic spectrum.
