Answer
$ln\frac{N_{t}}{N_{0}} = -\lambda t$
$ln\frac{Mass of fresh sample}{Mass of old sample} = -\lambda t$
Hence, $ln \frac{1}{x} = -1.21*10^{-4}*50000$
$x = 424$
$\%$ C-14 left = $\frac{1}{424} * 100\% = 0.24\%$
Work Step by Step
$ln\frac{N_{t}}{N_{0}} = -\lambda t$
$ln\frac{Mass of fresh sample}{Mass of old sample} = -\lambda t$
Hence, $ln \frac{1}{x} = -1.21*10^{-4}*50000$
$x = 424$
$\%$ C-14 left = $\frac{1}{424} * 100\% = 0.24\%$
