Answer
$ 0.22 nm$
Work Step by Step
Given, $n = 1$
$\theta = 23^{\circ}$
$d = 282 pm = 0.282 nm$
The wavelength of X-rays is
$2dsin\theta = n\lambda$
$\lambda = \frac{2dsin\theta}{n}= \frac{2 * 0.282nm (sin 23^{\circ})}{1} = 0.22 nm$
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