Answer
a) -196.15C°
b) -268.95C°
c) 327.85C°
Work Step by Step
0k-273.15=-273.15C°
a) 77k-273.15 = -196.15
b) 4.2k-273.15 = -268.95
c) 601k-273.15 = 327.85
Chemistry 12th Edition
by Chang, Raymond; Goldsby, Kenneth
Published by
McGraw-Hill Education
ISBN 10:
0078021510
ISBN 13:
978-0-07802-151-0
Chapter 1 - Intermolecular Forces and Liquids and Solids - Questions & Problems - Page 510: 11.26
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