Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 1 - Chemistry: The Study of Change - Questions & Problems: 1.81

Answer

Please see the work below.

Work Step by Step

We know that $(5.11\times 10^3Kg\space ore)\times \frac{34.63\%Cu}{100\%\space ore}\times \frac{1000g}{1Kg}=1.77\times 10^6gCu$
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