Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 1 - Chemistry: The Study of Change - Questions & Problems - Page 33: 1.79

Answer

t = 208 s or t = 3 min 28 s

Work Step by Step

$3 \space min = 180 \space s$ $$(180 + 43.13) \space s = 223.13 \space s$$ $$\frac{1609 \space m}{223.13 \space s} = 7.21 \space m/s$$ $$1500 \space m \times \frac{1 \space s}{7.21 \space m} = 208 \space s$$ $$208 \space s = 3 \space min \space 28 \space s$$
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