## Chemistry 12th Edition

$3.72\times10^{-3} g$ of lead
$10^6$g of blood contains $0.62 g$ of lead $6\times10^3$g of blood contains $x$ g of lead $\frac{0.62}{10^6}=\frac{x}{6\times10^3}$ $x=\frac{(6\times10^3)(0.62)}{10^6}$ $=3.72\times10^{-3} g$ of lead