Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 1 - Chemistry: The Study of Change - Questions & Problems - Page 31: 1.44


a) $118.39 in/s$ b) $180.38m/min$ c) $10.82km/h$

Work Step by Step

a) in/s 8.92 min for 1 mi (which is 63360 in) $1min=60seconds=\frac{63360}{8.92} in$ $\frac{63360}{8.92} in/s=frac{63360}{8.92\times60}$ $\approx 118.3856502242152466$ $=118.39 in/s$ b) m/min $1mi=1609m for 8.92 min$ $1 min = \frac{1609}{8.92} m$ $\approx180.3811659192825112m$ $=180.38m/min$ c) km/h $1609m=1.609km=\frac{8.92}{60}h$ $1h=\frac{(1.609\times60}{8.92}km$ $\approx 10.8228699551569507km/h$ $=10.82km/h$
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