Answer
a.)
5.60 g N* (1 mole N/14.01 g N) = 0.3997 g
14.2 g Cl*(1 mole Cl/ 35.45 g Cl)= 0.4006 g
0.800 g H*(1 mole H/1.01 g H)= 0.7921 g
0.3997/ 0.3997= 1
0.4006/0.3997= 2
0.7921/ 0.3997= 2
NClH3
Work Step by Step
b)
26.2 % N= 26.2 g N* (1 mole N/ 14.01 g) = 1.869
66.4% Cl = 66.4 g Cl*(1 mole/ 35.45 g)= 1.873
7.5% H= 7.5 g H* (1 mole/ 1.01 g)= 7.426
1.869/1.869= 1
1.873/1.869= 1
7.426/1.869= 4
NClH4
