Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 2 - Chemical Formulas and Composition Stoichiometrhy - Exercises - Composition Stoichiometry - Page 76: 49

Answer

$C_3H_8O$

Work Step by Step

Divide each percentage by the atomic mass of each element to find: $ C: \frac{60}{12}=5$ $H: \frac{13.33}{1}=13.33$ $O: \frac{26.67}{16}\approx1.67$ Find the atomic ratio by dividing each value to the lowest one: $C:H:O=\frac{5}{1.67}:\frac{13.33}{1.67}:\frac{1.67}{1.67}=3:8:1$ Hence, the empirical formula for the alcohol is $C_3H_8O$ The molecular formula of the compound is $(C_3H_8O)_n$. To find $n$, compute the molecular mass of the alcohol: $$M=(3\cdot12+8\cdot1+16)\cdot n=60n$$ It is given that the molecular mass is $60$, hence $60n=60$. By solving for $n$, it follows that $n=1$. Hence the molecular formula of the alcohol is $C_3H_8O$.
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