Answer
Comparing the equation with the general form $ax^{2}+bx+c$,
we get
a=1, b= -4 and c=13.
$b^{2}-4ac$ is less than 0.
Therefore, the solutions are given by
$x= \frac{-b±\sqrt {4ac-b^{2}}i}{2a}=\frac{4±\sqrt {4\times1\times13-16}i}{2}$
or $x=2+3i$ or $x=2-3i$.
Hence proved.
Work Step by Step
See the answer above.
