Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 8 - Section 8.1 - Complex Numbers - 8.1 Problem Set - Page 426: 73

Answer

$\frac{13}{15}-\frac{2}{5}i$

Work Step by Step

$\frac{5+4i}{3+6i}$ =$\frac{5+4i}{3+6i}\times\frac{3-6i}{3-6i}$ =$\frac{5(3-6i)+4i(3-6i)}{3^{2}-(6i)^{2}}$ =$\frac{15-30i+12i-24i^{2}}{9-36i^{2}}$ =$\frac{15-18i-24(-1)}{9-36(-1)}$ =$\frac{39-18i}{45}$ =$\frac{3(13-6i)}{45}$ =$\frac{(13-6i)}{15}$ =$\frac{13}{15}-\frac{6i}{15}$ =$\frac{13}{15}-\frac{2}{5}i$
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