Answer
$13$
Work Step by Step
$z_{2}z_{1}$
=$(2-3i)(2+3i)$
=$2(2+3i)-3i(2+3i)$
=$4+6i-6i-9i^{2}$
=$4-9(-1)$
=$4+9$
=$13$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.