Answer
$A=30^{\circ},b=20ft,a=2ft$
Using laws of sines,
$\frac{sinA}{a}=\frac{sinB}{b}$
or $\frac{sin30^{\circ}}{2}=\frac{sinB}{20}$
or $sinB=10\times\frac{1}{2}=5$
Now since$-1\leq\,sinB\leq1$,$ \,\,sinB=5\,\, $is not possible.
So, no triangle is possible.
Work Step by Step
$A=30^{\circ},b=20ft,a=2ft$
Using laws of sines,
$\frac{sinA}{a}=\frac{sinB}{b}$
or $\frac{sin30^{\circ}}{2}=\frac{sinB}{20}$
or $sinB=10\times\frac{1}{2}=5$
Now since$-1\leq\,sinB\leq1$,$ \,\,sinB=5\,\, $is not possible.
So, no triangle is possible.