Answer
$B=16^{\circ},b=1.4ft,c=4.4ft$
Work Step by Step
$A=43.5^{\circ}, C=120.5^{\circ},a=3.48 ft$
Therefore, $B=180^{\circ}-(A+C)=180^{\circ}-(43.5^{\circ}+120.5^{\circ})\,\,\,\,\,\,\,\,=180^{\circ}-164^{\circ}=16^{\circ}$
$So, B=16^{\circ}$
Using the laws of sines,
$\frac{sin A}{a}=\frac{sin B}{b}$
or, $\frac{sin 43.5^{\circ}}{3.48}=\frac{sin 16^{\circ}}{b}$
or, $b=1.4 ft$
Again, $\frac{sin B}{b}=\frac{sin C}{c}$
or, $\frac{sin 16^{\circ}}{1.4}=\frac{sin 120.5^{\circ}}{c}$
or, $c=4.4 ft$
So, $B=16^{\circ},b=1.4ft,c=4.4ft$
