Answer
$A=90^{\circ},a=10.9ft,c=10.6ft$
Work Step by Step
$B=14.33^{\circ},C=75.67^{\circ},b=2.72ft$
$So, A=180^{\circ}-(B+C)=180^{\circ}-(14.33^{\circ}+75.67^{\circ})=90^{\circ}$
Using laws of sines,
$\frac{sin A}{a}=\frac{sin B}{b}$
$\frac{sin 90^{\circ}}{a}=\frac{sin 14.33^{\circ}}{2.72}$
So, $a=10.9 ft$
Again, $\frac{sin B}{b}=\frac{sin C}{c}$
$\frac{sin 14.33^{\circ}}{2.72}=\frac{sin75.67^{\circ}}{c}$
so, $c=10.6ft$
So, $A=90^{\circ},a=10.9ft,c=10.6ft$
