Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 5 - Section 5.5 - Additional Identities - 5.5 Problem Set - Page 311: 30

Answer

$\dfrac{1}{2} [\sin{10x}+ \sin{6x}]$

Work Step by Step

$\cos{A} \sin{B} =\dfrac{1}{2}[\sin{(A+B)}- \sin{(A-B)}]$ $\cos{2x} \sin{8x} = \dfrac{1}{2} [\sin{10x} - \sin{(-6x)}]$ $\cos{2x} \sin{8x} = \dfrac{1}{2} [\sin{10x}+ \sin{6x}]$
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