Answer
$\dfrac{\sqrt{9-x^2}}{x}$
Work Step by Step
$\theta = \sin^{-1} {\dfrac{x}{3}}$
$\sin{\theta} =\dfrac{x}{3}$
$\cos{\theta} =\sqrt{1-\sin^2{\theta}} = \dfrac{\sqrt{9-x^2}}{3}$
$\cot{\theta} =\dfrac{\cos{\theta}}{\sin{\theta}} = \dfrac{\sqrt{9-x^2}}{x}$
