Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 5 - Section 5.5 - Additional Identities - 5.5 Problem Set - Page 311: 15



Work Step by Step

$\theta =\sin^{-1} {x}$ $\sin{\theta} =x$ $\cos{\theta} =\sqrt{1-\sin^2{\theta}} = \sqrt{1-x^2}$ $\tan{\theta} =\dfrac{\sin{\theta}}{\cos{\theta}} = \dfrac{x}{\sqrt{1-x^2}}$
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