Answer
$\dfrac{\sqrt{10}}{10}$
Work Step by Step
$\cos{B} =\sqrt{1-\sin^2{B}} = 0.8$
$\sin{\dfrac{B}{2}} = \sqrt{\dfrac{1-\cos{B}}{2}} = \sqrt{\dfrac{1-0.8}{2}}$
$\sin{\dfrac{B}{2}} = \dfrac{\sqrt{10}}{10}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 5 - Section 5.4 - Half-Angle Formulas - 5.4 Problem Set - Page 304: 33
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