Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 5 - Section 5.4 - Half-Angle Formulas - 5.4 Problem Set - Page 304: 20

Answer

$2$

Work Step by Step

From problem 17 $\to \sin{\dfrac{A}{2}} = \dfrac{1}{2}$ $\because \csc{\dfrac{A}{2}} = \dfrac{1}{\sin{\dfrac{A}{2}}}$ $\csc{\dfrac{A}{2}} = 2$
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