Answer
$\tan2y = \frac{2\tan y}{1-\tan^{2}y}$
Work Step by Step
By the double angle formula of tangent
$\tan2A = \frac{2\tan A}{1-\tan^{2}A}$
Replace "A" by "y" we get
$\tan2y = \frac{2\tan y}{1-\tan^{2}y}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 5 - Section 5.3 - Double-Angle Formulas - 5.3 Problem Set - Page 296: 3
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