Answer
$\dfrac{4}{3}$
Work Step by Step
$\cot{2x} = \dfrac{\cos{2x}}{\sin{2x}}$
$\cos{2x} = -\dfrac{4}{5} \hspace{30pt} \sin{2x} = - \dfrac{3}{5}$
$\therefore \cot{2x} = \dfrac{4}{3}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 5 - Section 5.3 - Double-Angle Formulas - 5.3 Problem Set - Page 296: 13
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